Wednesday, November 29, 2006

Trigonometry homework

b) sin 67 = x/17, so x = 17 sin 67

c) the two missing angles are tan-1 (4.32/3.65) and tan-1 (3.65/4.32)
(of course you only need to work out one of the missing angles to find the third one as angles in a right angle add up to 180 degrees as we all know!!!)

d) tan 47 = x/4.56, so x = 4.56 tan 47

e) the two missing angles are sin-1 (3.62/7.95) and cos-1 (3.62/7.95)

f) the two missing angles are sin-1 (4.32/6.41) and cos-1 (4.32/6.41)

g) angle at wall is cos-1 (1.5/5)

Full answers in detail in class. Don't worry, it's only November!

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